General comments: Take care with scattering angle:
sometimes you need to use q
and othertimes 2q.
Symmetry answers generally very good
Christy De Meyer
Formula used:
I(l)/ I0(l)=
exp{-(m/r)l rx}
or:
10/108 = exp{-(230.11,3).x}
Comment: You seem to have made a mistake with the units?
2 Marks
Usually the beam stop is thicker because the X-ray beam is unfiltered and non-monochromated. As a result, X-rays with another energy (higher as well as lower) have to be captured too.
Comment: Correct, but you need to point out that the
higher energy X-rays are more penetrating.
1 Mark
This can be overcome by using a silicon single crystal sample holder covered by a very thin
"coating" of the organic powder (dusting the powder on the holder.)
Result: the peaks will be much sharper, but the intensities will be much less
reliable and smaller.
2 Marks
The characteristic feature of synchrotron radiation that is particularly beneficial for powder diffraction studies of organic powder samples,is the possibility to select the incident X-ray wavelength from the highly intense continuous synchrotron radiation source. Another wavelength then the usual Cu Ka1 radiation can be used as monochromatic indicent radiation. So the wavelength for organic materials can be chosen slightly above or well below any of the absorption edges of the elements in the sample.
The two design features of synchrotron angle-despersive powder diffractometers used: Debye Scherrer and Flat plate.
Comment: See model answer for this part
0 Mark
E = 12.398 / l
and
n.l = 2.d.sinq
results in:
C = E.d.sinq
(E in keV, d in Å, the C = 6,1993keVÅ)
So, d = C / (E.sinq)
for E = 20keV and 2q = 3.5°
or q = 1.75°
is d = 10.15Å
for E = 100keV and 2q = 3.5°
or q = 1.75°
is d = 2.03Å
Comment: You need to state explicitly the range;
otherwise answer is fine
4 Marks
Si(111) - d = 3.3136Å
l = 2.d.sin(qM/2)
wavelength l0 = 0.75Å
wavelength l1 = 0.65Å
Problem: change of the angle 2qM
Answer:
sin(qM0/2) = 0.75Å/(2x3.3136Å)
qM0 = 0.2268 rad
sin(qM1/2) = 0.65Å/(2x3.3136Å)
qM0 = 0.1965 rad
So the change in 2q = - 0.0303 rad
or the change in 2q = - 1° 44'
Comment: You need to take care with the angle here (see
model answer).
Also, you want to work in degrees and avoid minutes (and seconds) of a degree
as well.
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Minor comment: State explicitly that a is a glide
plane
1 Mark
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Comment: Wrong symmetry element
0 Marks
Comment: Symmetry element correct, but location in space
wrong
0.5 Marks
Comment: For ii and viii, you need to specify more
detail, i.e. translation is of type I and C, respectively.
-0.5 Marks