• Assignement 2 - Josef Buršík
  • 1. The thickness of lead foil required to attenuate a Cu Ka X-ray beam of intensity 108 photons/s down to 10 photons/s should be in my opinion 0.062 mm..

  • The main beam-stop for an unfiltered non-monochromated copper X-ray source is said to be usually much thicker than this value because it is necessery to filter off also the higher energy white radiation (l shorter then l of characteristic radiation) which is more penetraiting.
     

  • 2. The laboratory powder diffraction patterns of organic compounds are often broadened due to sample transparency because the organic materials contain only light elements such as C, H, N, and O (these elements have lower number of electrons). For such transparent samples, the X-rays penetrate deeper into the sample than let say in case of ordinary ceramics powder. Their path out of the sample will be seen by the detector at a slightly smaller 2q angle and this contribute to the broadening of the refletion lines.
  • With a laboratory diffractometer configured for Bragg-Brentano geometry this problem may be overcome by measuring organic samples in form of thin layers.

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    The characteristic feature of synchrotron radiation that is particularly beneficial for powder diffraction studies of organic powder samples in my opinion is:

    The two design features of synchrotron angle-dispersive powder diffractometers that enable this characteristic feature to be exploited in my opinion are   3. Combining the equation E = 12.398 / l with the Bragg's law in terms of photon energy gives the energy-dispersive form:
    E d sinq = C
  • where C has the value 6.1993 keV. After that we can write
  • d = C/(E.sinq.
  • Putting the given values of E (20 and 100 keV) in this equation we obtain that d(1) = 5. 077 (A), and d(2) = 1.015 (A).

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    4. The basis for the calculation is the Bragg law 2 d sinq = l, (where q = qM), which shall be fulfilled for difracted beam for both wavelengths (0.75 A, and 0.65A). When we calculate the angles q(1) andq(2) (using the d value for Si) we get values 6.8678° and 5.9485° for 0.75 A and 0.65 A wavelengths, respectively (e.g. q(1) = arcsin(0.75/2*3.136) = 6.86781°).  The monochromator have to be rotated by 0.91925° so that the incident angle would decrease form 6.8678° to 5.9485°. (The difference is 0.91925° and the D(2qM) = 1.8385°.)

    5. The corresponding symmetry elements of symmetry operators given bellow in my opinion are:

    -x, y, -z: a twofold rotation axes about the b-axis, i.e. about the line 0,y,0, going through the origin
     

    1/2+x, 1/2+y, 1/2+z: point X(x,y,z) is moved to 1/2 + x in a-direction (x coordinate of a point X(x,y,z) changed to x+1/2), to 1/2 + y in b - direction (y-coordinate of a point X(x,y,z) changed to y+1/2), to 1/2 + z in c - direction (z-coordinate of a point X(x,y,z) changed to z+1/2). If the z - coordinate would  changed to 1/2-z then the operator would be an n-glide plane perpendicular to the c-axis and passing through the point (0,0,1/2), i.e. the plane x,y,1/2 with translations 1/2 along both a and b. In the case 1/2+x, 1/2+y, 1/2+z the point is moved by the same distance (1/2 of given lattice parameter) in the all three dimensions without any reflection.
     

    -x, -y, -z: a centre of inversion located at the origin (point (0, 0, 0))
     

    -x, -y, 1/2+z: A 21 screw axis with a twofold rotation about the c-axis, passing through the origin, followed by a translation of 1/2 c along c
     

    x, y, -z: a mirror plane perpendicular to the c-axis and passing through the origin, i.e. the plane
    x,y,0
     

    1/2+x, -y, z: an a-glide plane perpendicular to the b-axis and passing through the origin, i.e. the plane x,0,z with a translation 1/2 along a
     

    1/2+x, -y, -z: a twofold rotation about the x-axis, followed by a 1/2 a translation along a, passing through the origin
     

    1/2+x, 1/2+y, z: point X(x,y,z) is moved to 1/2 + x in a-direction (x coordinate of a point X(x,y,z) changed to x+1/2), to 1/2 + y in b - direction (y-coordinate of a point X(x,y,z) changed to y +1/2), z - coordinate remains unchanged. If the z - coordinate would  changed to  -z then the operator would be an n-glide plane perpendicular to the c-axis and passing through the origin, i.e. the plane x,y,0 with translations 1/2 along both a and b. But in the case 1/2+x,1/2+y,z it is done only the translation to 1/2+x,1/2+y along a and b, resp., without reflection.
     

    1/2-x, 1/2-y, z: a twofold rotation about the z-axis, passing trough the point (1/4, 1/4, z)
     

    x, 1/2-y, z: a mirror plane perpendicular to the b-axis and passing through the point (0, 1/2, 0), i.e. the plane x,1/2, z.