General comment: tags should not be used in title strings

Assignment Problem Set 6
by Nicki Agron-Olshina



Problem 1

This material belongs to the Monoclinic Crystal System and its unit cell is: a = 23.742, b = 6.181, c = 11.032, a = 90.00°, b = 97.83°, g = 90.00°.

The 2q values of the peaks used in the indexing program are in the following table.
2qI(obs)  2qI(obs)  2qI(obs)  2qI(obs) 
7.5067  16.09199  18.07740  20.8465
8.077727  16.442838  18.27185  21.64685
10.253634  16.64108  18.812587  22.67228
14.821731  16.90448  19.361031  23.101897
15.05557  17.151861  20.63680  23.451897

Peaks with lowest 2q values are preferable for indexing, even though they provide the least accurate lattice parameters. If hkl triplets are assigned to high-angle data based on poor values of the latice parameters, then the probability of assigning an incorrect hkl value increases rapidly with increasing 2q value.

2 Marks

As a novice at indexing I think I encountered every difficulity possible with this indexing problem. I believe that "Note 2; all the peaks are genuine unless indicated otherwise: etc" let me to include in the initial indexing a weak intensity peak that is apparently from an impurity phase.

Initially the twenty peaks with the lowest 2q values were used for indexing but with this combination of peaks none of the 10 most probable solutions produced valid results. A hint was received to eliminate one of the low intensity peaks from among the 21 peaks of lowest 2q value. I tried the Zone -Indexing Program five times, each time eliminating one of those peaks with the lowest 2q values. When the peak at 11.77 °2q was eliminated the the Zone-Indexing Program produced acceptable results as shown in the tables below.

The 10 Most Probable Solutions

N Q(A) Q(B) Q(C) Q(D) Q(E) Q(F) Lines
Indexed
Figure
 of Merit 
Lattice
Type
1 18.08 261.78 83.72 0.00 10.60 0.00 20 17.4P
2 18.08 261.78 83.72 0.00 10.60 0.00 20 17.3P
3 18.08 261.78 83.72 0.00 10.60 0.00 20 17.3P
4 38.83 33.57 30.46 -6.21 25.42 0.00 20 3.7P
5 29.49 28.06 38.05 17.60 23.45 17.82 20 3.3P
6 38.53 33.50 27.63 -6.87 23.70 0.00 20 2.2P
7 16.30 17.89 38.26 13.10 13.28 0.00 20 2.2P
8 72.32 31.56 74.61 22.33 9.21 30.50 19 8.4P
9 57.99 18.09 83.64 10.60 23.60 10.80 19 5.8P
10 49.35 33.77 72.45 3.61 17.11 0.00 19 4.1P

The Equivalent Real-Space Unit Cells

N        a (Å) b (Å) c (Å) a (°) b (°) g (°) V (Å3)  
1 23.742 6.181 11.032 90.00 97.83 90.00 1603.7    
2 23.742 6.181 11.032 90.00 97.83 90.00 1603.7    
3 23.742 6.181 11.032 90.00 97.83 90.00 1603.7    
4 17.284 17.355 19.608 84.00 111.80 92.22 5431.3    
5 20.245 20.184 17.595 100.41 106.93 103.81 6432.6    
6 17.309 17.407 20.572 83.04 111.44 92.54 5726.6    
7 25.759 24.484 17.367 105.06 105.94 85.91 10170.1    
8 12.409 19.266 11.897 102.83 89.33 108.29 2627.9    
9 13.471 23.992 11.164 96.38 98.64 98.46 3495.6    
10 14.383 17.220 11.879 92.12 98.23 89.70 2909.8    

2 Marks

Comment: Expected difficulties not discussed

Problem 2

This material belongs to the Monoclinic crystal system because a=23.742, b=6.181, c=11.032 and a = 90.00°, b = 97.83°, g = 90.00°, therefore a ¹b¹c and a = b = 90° ¹ g.

Minor comment: You have a typographical error with the Greek characters here

The hkl values in the following table were used to determine that this material has a Primitive lattice centring.

The International Tables for X-Ray Crystallography was used to compare the hkl values of this material to the general conditions limiting possible reflections for all the Monoclinic Space Groups with b as the unique axis. The P2, Pm and P2/m Space Groups are possible because they have no conditions limiting possible reflections. The P21 and P21/m Space Groups could not be eliminated as possibilities despite their reflection condition, 0k0: k=2n, because the reflection, 0k0, was simple not observed in this material.

The remaining Monoclinic Space Groups, C2, Pc, Cm, Cc, C2/m, P2/c, P21/c and C2/c all had at least one of their general conditions for limiting possible reflections violated by an observed hkl reflection.

Comment: You were asked to determine the Bravais lattice only at this point (not space group symmetry)

1 Mark

Table of the reflection indicies, observed peak positions and matching calculated values
    h       k       l     2qobs (°)   2qcalc (°)
2   0   0   7.5000 7.511
0   0   1   8.0700 8.083
-2   0   1   10.2500 10.263
2   0   1   11.7700 11.771
1   1   0   14.8200 14.806
4   0   0   15.0500 15.054
-4   0   1   16.0900 16.101
0   1   1   16.4400 16.463
-1   1   1   16.6400 16.641
-2   0   2   16.9000 16.920
1   1   1   17.1500 17.137
4   0   1   18.0700 18.063
3   1   0   18.2700 18.262
2   0   2   18.8100 18.800
-3   1   1   19.3600 19.357
3   1   1   20.6300 20.622
4   1   0   20.8400 20.833
-1   1   2   21.6400 21.632
6   0   0   22.6700 22.664
4   1   1   23.1000 23.125
-3   1   2   23.4500 23.445
5   1   0   23.7700 23.750
-5   1   1   24.2700 24.263
0   0   3   24.4100 24.413
-2   0   3   24.5400 24.556

Comment: No mention made of overlapped reflections?

2 Marks

Problem 3

This material has one glide plane, a^y because the reflection condition, h0l: h=2n, is met by many observed peaks (eg 200, 001, -201, 201, etc) and is not negated by any observable reflection.

Excellent

5 Marks

This material has one screw axis parallel to the a axis because the reflection condition, h00: h=2n, is met by several observed peaks (eg 002, 004, 006) and is not negated by any observable reflection.

Comment: Wrong direction chosen

0 Marks

Problem 4

The most likely space group for this material is P21/a.

Comment: Correct choice despite the above error!

2 Marks

Parden my ignorance, but the only thing I find surprising about my answer is that I arrived at it at all and on time.

Comment: Centrosymmetric space groups for natural products are not very common

0 Marks

Problem 5

2q   h   k   l     2q   h   k   l     2q   h   k   l
  7.50 200  14.82 110  16.90 -202
  8.07 001  15.05 400  17.15 111
10.25 -201  16.09 -401  18.07 401
11.77 201  16.64 -111  18.27 310

2 Marks

          a (Å) b (Å) c (Å) a (°) b (°) g (°)
Value 23.72856 6.17111 11.03219 90.0000 97.9013 90.0000
ESD 0.00822 0.00189 0.00453 0.0000 0.0157 0.0000

Comment: Should quote less digits, also no decimal places for angles fixed exactly at 90°

2 Marks

Comment: Zero value?

0 Marks

Although lower estimated standard deviations were obtained (I actually tried it) by including higher angle data in the Program to Refine Unit-Cell Parameters, it was not suitable in this case for two reasons:

1. The 16 highest angle peaks (excluding the impurity peak) resulted in five of the peaks being rejected by the Program to Refine Unit-Cell Parameters. Even though the error values were lower, this looked pretty suspect because of the rejected peaks.

2. There is some uncertainity in two of the higher angle peaks due to peak broadening and one higher angle peak has a noticeable tail on the high-angle side.

Comment: See model answer

1 Mark

General comment: well done in places, but lack of understanding in other places.