| Questions | Answers | |
|---|---|---|
| The Unit Cell | due to the packing of the atom/molecule in a crystal | 0 Marks |
| The Crystal Lattice | due to the packing of the atom/molecule in a crystal | 1 Mark |
| The origin in reciprocal lattice | Chosen by the crystallographer | 0 Marks |
| The origin in the crystal | Chosen by the crystallographer | 1 Mark |
| The space group symmetr of the crystal | Chosen by the crystallographer | 0 Marks |
Comment: A nice table. See model answers for correct solution.
When a center of symmetry acts on a
point at coordinates (x,y,z) it converts to a point at (-x, -y, -z).
The same coordinates can be obtained if we perform 2/m operation i.e C2 axis along b and mirror along
ac plane.
Similarly, in an ortho rhombic unit cell if a center of symmetry were addded to 222 groups (which is
non-centrosymmetric) they become equal to a centrosymmetric 2/m2/m2/m. Measurement of a centrosymmetric
property on a non-centrosymmetric crystal causes the it to rewpond as if it possessed a center of
symmetry. Such classes or groups are called Laue groups.
Comment: Examples OK, but explanation could be
better.
1 + 2 Marks
Crystallographic symmetry operations may be grouped into 5 distinct groups,
namely, lattice translations, rotations, rotary-inversions, screw-rotations,
and mirror/glide planes.
(Part of question left in accidently at this
point?)
the molecule does not possess any symmertry operations. This is further confirmed
by its optical activity (dextro rotatory)
It is better to use .gif files for pictures
(or .jpg for photos) since these are compressed, whereas windows .bmp
files are uncompressed and very large. [I converted your .bmp file
to .gif]. Please avoid the use of scanned
images (which should not be required for any coursework) since there
is always the risk of copyright infringement with their use. You also
need to specify the correct size within the IMG tag, which I have corrected
here.
Comment: The question is concerned with
crystal structure symmetry, and not meolcular - see model answer.
0 Marks
The co-ordinates for the organo metallic Co compound viewing down the c-axis is worked out to ab as follows;
Since Cobalt forms predominantly Octahedral complexes with m-3m point group symmetry
it is expected to occupy special positions.
Comment: Please see model answer for how to attempt
this question.
0 Marks
The diagram indicates the staggered conformation of 1,2-dichloro ethane.
There is a center of inversion (i) between the two carbon atoms (seen clearly from view A)
Therefore the point group symmetry for this molecule is -1.
Comment: You have missed two of the symmetry elements
present, and so the end deduction is incorrect.
2 Marks
(i) The diagram indicates the following 3 types of symmetry elements
Comment: File seemed to end here?
Overall comments: Check that you understand the
model answers. If not please email us with questions on anything that
you don't understand or are unsure about.